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Author SHA1 Message Date
9a3775bf5d Add alternative windows renamer 2024-01-09 19:29:33 -06:00
ffc8664553 Add alternative windows renamer 2024-01-09 19:29:25 -06:00
3 changed files with 67 additions and 53 deletions

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#!/bin/bash
# Old version:
# for f in ./*'('*')'*; do mv -i "$f" "${f/ (*)/}"; done
# for f in ./*/*'('*')'*; do mv -i "$f" "${f/ (*)/}"; done
#!/bin/bash
# Recursively find all files with parentheses in the name
find . -type f -name '*(*' -print0 | while IFS= read -r -d '' file; do
# Extract the new filename without parentheses
new_name=$(echo "$file" | sed 's/ ([^)]*)//g')
# Check if the new name is different from the current name
if [ "$file" != "$new_name" ]; then
# Rename the file
mv -i "$file" "$new_name"
echo "Renamed: $file to $new_name"
fi
done

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#!/bin/bash
# Recursively find all files with parentheses in the name
find . -type f -name '*(*' -print0 | while IFS= read -r -d '' file; do
# Extract the date from the parentheses using awk
date_in_parentheses=$(echo "$file" | awk -F'[()]' '{print $2}')
# Convert the date to a format that can be compared
formatted_date=$(date -d "$date_in_parentheses" +"%Y_%m_%d %H_%M_%S %Z" 2>/dev/null || echo "$date_in_parentheses")
# Check if the formatted date is valid
if [ -n "$formatted_date" ]; then
# Create a temporary directory for duplicates
temp_dir=$(mktemp -d)
# Move all files with the same content inside parentheses to the temporary directory
find . -type f -name "*($date_in_parentheses)" -exec mv -i {} "$temp_dir" \;
# Find the newest file in the temporary directory
newest_file=$(ls -t "$temp_dir" | head -n 1)
# Move the newest file back to the original location
if [ -n "$newest_file" ]; then
mv -i "$temp_dir/$newest_file" "$file"
echo "Kept: $file and removed older duplicates"
fi
# Remove the temporary directory
rm -r "$temp_dir"
else
echo "Skipping $file due to invalid date format in parentheses"
fi
done

67
win_fh_rename.py Executable file
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#!/usr/bin/python3
# Solution inspired by: https://gist.github.com/kmorcinek/2710267
# This script will convert the date between the parentehsis and get the oldest date
# It will delete the older files and search all sub directories
# This definitely isn't the most efficient, but can process tens of thousands of files in less than a second
import re
from os.path import join
import os.path
from os import walk, rename, remove
import os
import sys
from datetime import datetime
FOLDER_PATH = os.getcwd()
processed = []
for path, subdirs, files in walk(FOLDER_PATH):
for i, name in enumerate(files): # Iterate over the original list
if name in processed:
continue
print('{} / {}'.format(i + 1, len(files)))
# Extract the date from the parentheses using regex
match = re.search(r'\((\d{4}_\d{2}_\d{2} \d{2}_\d{2}_\d{2} UTC)\)', name)
if match:
date_in_parentheses = match.group(1)
# Convert the date to a datetime object for comparison
formatted_date = datetime.strptime(date_in_parentheses, "%Y_%m_%d %H_%M_%S %Z")
# Find all files that match regex
duplicates = [f for f in files if re.sub(r' \(.+\)', '', f) == re.sub(r' \(.+\)', '', name)]
# Find the newest file among duplicates
newest_file = max(duplicates, key=lambda f: datetime.strptime(re.search(r'\((\d{4}_\d{2}_\d{2} \d{2}_\d{2}_\d{2} UTC)\)', f).group(1), "%Y_%m_%d %H_%M_%S %Z"))
print("Newest file found:", newest_file)
# Rename the current file if needed
new_name = re.sub(r' \(.+\)', '', newest_file)
# Move older duplicates to the fixed directory
for duplicate in duplicates:
duplicate_path = join(path, duplicate)
if duplicate != newest_file:
# Check if file exists because it can be deleted already
if os.path.isfile(duplicate_path):
remove(duplicate_path)
print(f"Removed older duplicate: {duplicate_path}")
else:
if os.path.isfile(duplicate_path):
rename(join(path, newest_file), join(path, new_name))
print(f"Renamed: {duplicate_path} to {join(path, new_name)}")
processed.append(duplicate_path)
else:
print(f"Skipping {join(path, name)}")
print(f"Processed {len(processed)} files.")